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2009年3月10日 星期二

作業4:複利計算

借錢500萬,年利18%,每月複利計算,請問連本帶利的金額
5, 10, 15, 20, 25, 30, 35, 40, 45, 50年的金額。並比較公式:

A*exp(0.18n)

A*(1+0.18/12)^(12*n), n=年數, A=本金

hint: math.h, pow, exp

66 則留言:

  1. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {   
        int A=5000000;
        float B,C;
        float x=1+0.18/12;
        int i;
        for (i=5; i<=50; i=i+5)
        {
        B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f\t %f\n",i,B,C);
        }
        system("pause");
        return 0;
    }

    回覆刪除
  2. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for (i=5; i<=50; i=i+5)
        {
            B=A*pow(x,12.*i);
            C=A*exp(0.18*i);
            printf("%d-->%f\t %f\n",i, B, C);
        }
        system("Pause");
        return 0;
    }

    回覆刪除
  3. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main(){
    int A=5000000;
    float B,C;
    float x=1+0.18/12;
    int i;
    for (i=5;i<=50;i=i+5)
    {
    B=A*pow(x,12.*i);
    C=A*exp(0.18*i);
    printf("%d-->%f \t %f\n",i, B , C);
    }

    system("Pause");
    return 0;
    }

    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  4. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for (i=5; i<=50; i=i+5)
        {
            B=A*pow(x,12.*i);
            C=A*exp(0.18*i);
            printf("%d-->%f\t %f\n",i, B, C);
        }
        system("Pause");
        return 0;
    }
    答案:
    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  5. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for(i=5; i<=50; i=i+5)
        {
            B=A*pow(x,12.*i);
            C=A*exp(0.18*i);
            printf("%d-->%f\t %f\n",i, B, C);
        }
            system("Pause");
            return 0;   
    }

    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  6. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main() {
        int A=5000000;
        float B, C ;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
              {
                 B=A*pow(x,12.*i);
                 C=A*exp(0.18*i);
                 printf("%d-->%f\t %f\n",i, B,C);
              }
        system("pause");
        return 0;
    }

    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000

    回覆刪除
  7. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B,C;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
        {
            B=A*pow(x,12.*i);
            C=A*exp(0.18*i);
            printf("%d-->%f\t %f\n",i,B,C);
         }
        system("pause");
        return 0;
    }


    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000

    回覆刪除
  8. #include<stdio.h>
    #include<stdlib.h>
    #include<math.h>
    int main()
    {
    int A=5000000;
    float B,C;
    float x=1+0.18/12;
    int i;
    for(i=5;i<=50;i=i+5)
    {
    B=A*pow(x,12*i);
    C=A*exp(0.18*i);
    printf("%d-->%f\t %f\n",i,B,C);
    }
    system("pause");
    return 0;
    }





    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除

  9. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main () {
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for (i=5; i<=50; i=i+5)
        {
            B=A*pow(x,12.*i);
            C=A*exp(0.18*i);
            printf("%d-->%f \t %f\n",i,B,C);
        }             
        system("Pause");
        return 0;
    }

    5-->12216089.000000      12298016.000000
    10-->29846564.000000     30248238.000000
    15-->72921656.000000     74398656.000000
    20-->178163472.000000    182991168.000000
    25-->435292160.000000    450085664.000000
    30-->1063513536.000000   1107032064.000000
    35-->2598395136.000000   2722859520.000000
    40-->6348444672.000000   6697154048.000000
    45-->15510632448.000000          16472340480.000000
    50-->37895852032.000000          40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  10. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {   
        int A=5000000;
        float B,C;
        float x=1+0.18/12;
        int i;
        for (i=5; i<=50; i=i+5)
        {
        B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f\t %f\n",i,B,C);
        }
        system("pause");
        return 0;
    }

    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  11. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main ()
    {
         int A=5000000;
         float B , C;
         float x=1+0.18/12;
         int i;
         for (i=5 ; i<=50 ; i=i+5)
         {
             B=A*pow (x,12.*i);
             C=A*exp (0.18*i);
             printf("%d-->%f;\t %f \n",i ,B ,C);
         }
         system("pause");
         return 0;
    }


    答案:37895852032 , 40515420160

    回覆刪除
  12. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main ()
    {
        int a=5000000;
        float b, c ;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
        {
         b=a*pow(x,12.*i);
         c=a*exp(0.18*i);
         printf("%d-->%f\t %f\n",i,b,c);
        }
        system("pause");
        return 0;
    }

    答案:
    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000

    回覆刪除
  13. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main ()
    {
         int A=5000000;
         float B,C ;
         float x=1+0.18/12;
         int i;
         for (i=5 ; i<=50 ; i=i+5)
         {
             B=A*pow (x,12.*i);
             C=A*exp (0.18*i);
             printf("%d-->%f;\t %f \n",i ,B ,C);
             }
             system("pause");
             return 0;
    }
    答案:37895852032 40515420160

    回覆刪除
  14. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main() {
        int A =5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50; i=i+5)
        {
        B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f \t %f\n",i, B, C);
        }
        system("pause");
        return 0 ;
    }


    答案:5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  15. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main(){
        int A=5000000;
        float B,C;
        float x=1+0.18/12;
        int i;
        for (i=5; i<=50; i=i+5)
        {
        B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f \t %f\n",i, B, C);
        }
        system("pause");
        return 0;
    }

    答案:
    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  16. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main ()
    {
         int A=5000000;
         float B , C;
         float x=1+0.18/12;
         int i;
         for (i=5 ; i<=50 ; i=i+5)
         {
             B=A*pow (x,12.*i);
             C=A*exp (0.18*i);
             printf("%d-->%f;\t %f \n",i ,B ,C);
         }
         system("pause");
         return 0;
    }


    答案

    5-->12216089.000000; 12298016.000000
    10-->29846564.000000; 30248238.000000
    15-->72921656.000000; 74398656.000000
    20-->178163472.000000; 182991168.000000
    25-->435292160.000000; 450085664.000000
    30-->1063513536.000000; 1107032064.000000
    35-->2598395136.000000; 2722859520.000000
    40-->6348444672.000000; 6697154048.000000
    45-->15510632448.000000; 16472340480.000000
    50-->37895852032.000000; 40515420160.000000

    回覆刪除
  17. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A =5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for(i=5;i<=50;i=i+5)
        {
                          B=A*pow(x,12.*i);
                          C=A*exp(0.18*i);
                          printf("%d-->%f \t %f\n",i, B, C);
        }
        system("pause");
        return 0;
    }

    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  18. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main ()
    {
        int A =5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for(i=5;i<=50;i=i+5)
        {
                         B=A*pow(x,12.*i);
                         C=A*exp(0.18*i);
                         printf("%d-->%f \t %f\n",i,B,C);
        }
        system("pause");
        return 0;
       
    }



    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  19. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B,C;
        float x=1+0.18/12;
        int i;
        for(i=5;i<=50;i=i+5)
        {
         B=A*pow(x,12.*i);
         C=A*exp(0.3*i);
         printf("%d-->%f\t,%f\n",i,B,C);
         }
        system("pause");
        return 0;
         
    }


    ans:
    5-->12216089.000000 ,22408446.000000
    10-->29846564.000000 ,100427688.000000
    15-->72921656.000000 ,450085664.000000
    20-->178163472.000000 ,2017143936.000000
    25-->435292160.000000 ,9040211968.000000
    30-->1063513536.000000 ,40515420160.000000
    35-->2598395136.000000 ,181577515008.000000
    40-->6348444672.000000 ,813773946880.000000
    45-->15510632448.000000 ,3647081807872.000000
    50-->37895852032.000000 ,16345087344640.000000
    請按任意鍵繼續 . . .

    回覆刪除
  20. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B,c;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
    {
        B=A*pow(x,12.*i);
        c=A*exp(0.3*i);
        printf("%d-->%f\t %f\n",i,B,c);
    }
        system("pause");
        return 0;
    }

    ANS:

    5-->12216089.000000 22408446.000000
    10-->29846564.000000 100427688.000000
    15-->72921656.000000 450085664.000000
    20-->178163472.000000 2017143936.000000
    25-->435292160.000000 9040211968.000000
    30-->1063513536.000000 40515420160.000000
    35-->2598395136.000000 181577515008.000000
    40-->6348444672.000000 813773946880.000000
    45-->15510632448.000000 3647081807872.000000
    50-->37895852032.000000 16345087344640.000000
    請按任意鍵繼續 . . .

    回覆刪除
  21. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B,C;
        float x=1.+0.18/12;
        int i;
        for(i=5;i<=50;i=i+5)
        {
        B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f\t %f\n",i,B,C);
        }
        system("Pause");
        return 0;
    }

    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000

    回覆刪除
  22. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=500000;
        float B,C;
        float x=1.+0.18/12;
        int i;
        for(i=5;i<=50;i=i+5)
        {
        B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f\t %f\n",i,B,C);
        }
        system("Pause");
        return 0;
    }





    5-->1221608.875000 1229801.500000
    10-->2984656.500000 3024823.750000
    15-->7292165.500000 7439866.000000
    20-->17816348.000000 18299118.000000
    25-->43529216.000000 45008564.000000
    30-->106351352.000000 110703208.000000
    35-->259839504.000000 272285952.000000
    40-->634844480.000000 669715392.000000
    45-->1551063296.000000 1647234048.000000
    50-->3789585152.000000 4051542016.000000

    回覆刪除
  23. #include <math.h>
    #include <stdio.h>
    #include <stdlib.h>
    int main()
    {
        int A=5000000;
        float B,c;
        float x=1+0.18/12;
        int i;
        for (i=5; i<=50; i=i+5)
        {
        B=A*pow(x,12.*i);
        c=A*exp(0.3*i);
        printf("%d-->%f\t %f\n",i,B,c);
    }
        system("pause");                               
        return 0;
    }

    ANS:

    5-->12216089.000000 22408446.000000
    10-->29846564.000000 100427688.000000
    15-->72921656.000000 450085664.000000
    20-->178163472.000000 2017143936.000000
    25-->435292160.000000 9040211968.000000
    30-->1063513536.000000 40515420160.000000
    35-->2598395136.000000 181577515008.000000
    40-->6348444672.000000 813773946880.000000
    45-->15510632448.000000 3647081807872.000000
    50-->37895852032.000000 16345087344640.000000
    請按任意鍵繼續 . . .

    回覆刪除
  24. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int a=5000000;
        float b,c;
        float x=1+0.18/12;
        int i;
        for (i=5; i<=50; i=i+5)
        {
        b=a*pow(x,12.*i);
        c=a*exp(0.18*i);
        printf("%d-->%f\t %f\n",i,b,c);
        }
        system("pause");
        return 0;
    }


    答案:
    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000

    回覆刪除
  25. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main(){
        int A=5000000;
        float B, c;
        float x=1+0.18/12;
        int i;
        for (i=5; i<=50; i=i+5)
        {
        B=A*pow(x,12.*i);
        c=A*exp(0.18*i);
        printf("%d-->%f \t %f\n",i, B,c);
    }
        system("Pause");
        return 0;
    }

    答案:
    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  26. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main ()
    {
         int A=5000000;
         float B,C ;
         float x=1+0.18/12;
         int i;
         for (i=5 ; i<=50 ; i=i+5)
         {
             B=A*pow (x,12.*i);
             C=A*exp (0.18*i);
             printf("%d-->%f;\t %f \n",i ,B ,C);
             }
             system("pause");
             return 0;
    }
    答案:
    5-->12216089.000000; 12298016.000000
    10-->29846564.000000; 30248238.000000
    15-->72921656.000000; 74398656.000000
    20-->178163472.000000; 182991168.000000
    25-->435292160.000000; 450085664.000000
    30-->1063513536.000000; 1107032064.000000
    35-->2598395136.000000; 2722859520.000000
    40-->6348444672.000000; 6697154048.000000
    45-->15510632448.000000; 16472340480.000000
    50-->37895852032.000000; 40515420160.000000

    回覆刪除
  27. #include <math.h>
    #include <stdio.h>
    #include <stdlib.h>
    int main()
    {
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
        {B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f \t %f\n",i,B,C);
        }system("pause");
        return 0;
    }

    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000

    回覆刪除
  28. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B, c;
        float x=1+0.18/12;
        int i;
        for (i=5; i<=50; i=i+5)
        {
         B=A*pow(x,12.*i);
         c=A*exp(0.18*i);
         printf("%d-->%f \t %f\n",i, B,c);
        }
        system("Pause");
        return 0;
    }

    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000

    回覆刪除
  29. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B,C;
        float x=1+0.18/12;
        int i;
        for(i=5;i<=50;i=i+5)
        {
         B=A*pow(x,12.*i);
         C=A*exp(0.18*i);
         printf("%d-->%f \t %f \n",i,B,C);
        }
         system("pause");
         return 0;
    }

    回覆刪除
  30. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main(){
        int  A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;   
        for (i=5;i<=50;i=i+5)
        {
            B=A*pow(x,12.*i);
            C=A*exp(0.18*i);
            printf("%d-->%f \t %f\n",i,B,C);
        }
        system("pause");
        return 0;
    }
    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  31. #include <stdlib.h>
    #include <stdio.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for(i=5; i<=50; i=i+5)
        {
          B=A*pow(x,12.*i);
          C=A*exp(0.18*i);
          printf("%d-->%f\t%f\n",i,B,C);
        }
        system("Pause");
        return 0;
    }


    Ans:
    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000

    回覆刪除
  32. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for(i=5;i<=50;i=i+5)
        {
          B=A*pow(x,12.*i);
          C=A*exp(0.18*i);
          printf("%d-->%f \t %f\n",i,B,C);
        }
        system("pause");
        return 0;
    }




    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000

    回覆刪除
  33. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B ,C ;
        float x=1.+0.18/12;
        int i;
        for(i=5 ;i<=50 ;i=i+5)
        {
        B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f\t %f\n",i ,B ,C);
        }       
        system("Pause");
        return 0;
    }

    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000

    回覆刪除
  34. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for(i=5;i<=50;i=i+5)
        {
         B=A*pow(x,12.*i);
         C=A*exp(0.18*i);
         printf("%d\n-->%f \t %f\n",i,B,C);
        }
        system ("pause");
        return 0;
    }

    5
    -->12216089.000000       12298016.000000
    10
    -->29846564.000000       30248238.000000
    15
    -->72921656.000000       74398656.000000
    20
    -->178163472.000000      182991168.000000
    25
    -->435292160.000000      450085664.000000
    30
    -->1063513536.000000     1107032064.000000
    35
    -->2598395136.000000     2722859520.000000
    40
    -->6348444672.000000     6697154048.000000
    45
    -->15510632448.000000    16472340480.000000
    50
    -->37895852032.000000    40515420160.000000

    回覆刪除
  35. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
        {
         B=A*pow(x,12.*i);
         C=A*exp(0.18*i);
         printf("%d\n-->%f \t %f\n",i, B, C);
         }
    system("pause");
    return 0;
    }

    5
    -->12216089.000000 12298016.000000
    10
    -->29846564.000000 30248238.000000
    15
    -->72921656.000000 74398656.000000
    20
    -->178163472.000000 182991168.000000
    25
    -->435292160.000000 450085664.000000
    30
    -->1063513536.000000 1107032064.000000
    35
    -->2598395136.000000 2722859520.000000
    40
    -->6348444672.000000 6697154048.000000
    45
    -->15510632448.000000 16472340480.000000
    50
    -->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  36. #include <math.h>
    #include <stdio.h>
    #include <stdlib.h>
    int main()
    {
        int A=5000000;
        float  B,C;
        float x=1+0.18/12;
        int  i;
        for  (i=5;i<=50;i=i+5)
        {B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f \t %f\n",i,B,C);
        }system("pause");
        return 0;
    }
    #include <math.h>
    #include <stdio.h>
    #include <stdlib.h>
    int main()
    {
        int A=5000000;
        float  B,C;
        float x=1+0.18/12;
        int  i;
        for  (i=5;i<=50;i=i+5)
        {B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f \t %f\n",i,B,C);
        }system("pause");
        return 0;
    }

    回覆刪除
  37. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B,C;
        float x=1.+0.18/12;
        int i;
        for(i=5;i<=50;i=i+5)
        {
        B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f\t %f\n",i,B,C);
        }
        system("Pause");
        return 0;
    }

    5-->12216089.000000      12298016.000000
    10-->29846564.000000     30248238.000000
    15-->72921656.000000     74398656.000000
    20-->178163472.000000    182991168.000000
    25-->435292160.000000    450085664.000000
    30-->1063513536.000000   1107032064.000000
    35-->2598395136.000000   2722859520.000000
    40-->6348444672.000000   6697154048.000000
    45-->15510632448.000000  16472340480.000000
    50-->37895852032.000000  40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  38. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main(){
    int A=5000000;
    float B,C;
    float x=1+0.18/12;
    int i;
    for(i=5; i<=50; i=i+5)
    {
    B=A*pow(x,12.*i);
    C=A*exp(0.18*i);
    printf("%d-->%f\t %f \n",i,B,C);
    }
    system("Pause");
    return 0;
    }
    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  39. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B,C;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
        {
         B=A*pow(x,12.*i);
         C=A*exp(0.18*i);
         printf("%d->%f \t %f \n",i,B,C);
        }
        system ("pause");
        return 0;
    }

    回覆刪除
  40. int A=5000000;
        float B, C;
        float X=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
        {B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f \t \n",i,B,C);
        }system("pause");
        return 0;

    回覆刪除
  41. include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B,C;
        float x=1+0.18/12;
        int i;
        for(i=5;i<=50;i=i+5)
        {
         B=A*pow(x,12.*i);
         C=A*exp(0.18*i);
         printf("%d-->%f\t %f \n",i,B,C);
        }
        system("pause");
        return 0;
    }
    5-->12216089.000000      12298016.000000
    10-->29846564.000000     30248238.000000
    15-->72921656.000000     74398656.000000
    20-->178163472.000000    182991168.000000
    25-->435292160.000000    450085664.000000
    30-->1063513536.000000   1107032064.000000
    35-->2598395136.000000   2722859520.000000
    40-->6348444672.000000   6697154048.000000
    45-->15510632448.000000  16472340480.000000
    50-->37895852032.000000  40515420160.000000

     

    回覆刪除
  42. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>

    int main ()
    {
    int A=5000000;
    float B, C;
    float x=1+0;18/12;
    int i;
    for (i=5;i<=50;i=i+5)
    {
    B=A*pow(x,12*1);
    C=A*exp (0.18*i);
    printf("%d-->%f \t %f\n",i,B,C);
    }
    system("pause");
    return 0;
    }

    回覆刪除
  43. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main(){
        int  A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;   
        for (i=5;i<=50;i=i+5)
        {
            B=A*pow(x,12.*i);
            C=A*exp(0.18*i);
            printf("%d-->%f \t %f\n",i,B,C);
        }
        system("pause");
        return 0;
    }
    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  44. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=500000;
        float B;
        float X=1+0.18/12;
        int i;
        for(i=5;i<=50;i=i+5)
       {
        B=A*pow(X,12.*i);
        printf("%f\n",B);
       }
        system("pause");
        return 0 ;
    }









    #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=500000;
        float B,C;
        float X=1+0.18/12;
        int i;
        for(i=5;i<=50;i=i+5)
       {
        B=A*pow(X,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f \t %f\n",i,B,C);
       }
        system("pause");
        return 0 ;
    }

    回覆刪除
  45. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
         int A=500000;
         float B,C;
         float X=1+0.18/12;
         int i;
         for(i=5;i<=50;i=i+5)
         {
          B=A*pow(X,12.*i );
          C=A*exp(0.18*i);                  
          printf("%d-->%f\t %f\n",i,B,C);
       
          }
          system("pause");
          return 0;
    }





    #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
         int A=500000;
         float B,C;
         float X=1+0.18/12;
         int i;
         for(i=5;i<=50;i=i+5)
         {
          B=A*pow(X,12.*i );
          C=A*exp(0.18*i);                  
          printf("%d-->%f\t %f\n",i,B,C);
       
          }
          system("pause");
          return 0;
    }

    回覆刪除
  46. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main(){
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for (i=5; i<=50; i=i+5)
        {
        B=A*pow(x,12.*1);
        C=A*exp(0.18*i);
        printf("%d-->%f \t %f\n",i, B, C);
        }
        system("pause");
        return 0;
    }

    回覆刪除
  47. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B,C;
        float x=1+0.18/12;
        int i;
        for(i=5;i<=50;i=i+5)
        {
         B=A*pow(x,12.*i);
         C=A*exp(0.18*i);
         printf("%d-->%f \t %f \n",i,B,C);     
        }
        system("pause");
        return 0;
    }

    回覆刪除
  48. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main(){
    int A=5000000;
    float B,C;
    float x=1+0.18/12;
    int i;
    for(i=5; i<=50; i=i+5)
    {
    B=A*pow(x,12.*i);
    C=A*exp(0.18*i);
    printf("%d-->%f\t %f \n",i,B,C);
    }
    system("Pause");
    return 0;
    }
    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  49. #include <math.h>
    #include <stdio.h>
    #include <stdlib.h>
    int main()
    {
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
        {B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f \t %f\n",i,B,C);
        }system("pause");
        return 0;
    }




    #include <math.h>
    #include <stdio.h>
    #include <stdlib.h>
    int main()
    {
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
        {B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f \t %f\n",i,B,C);
        }system("pause");
        return 0;
    }

    回覆刪除
  50. #include <math.h>
    #include <stdio.h>
    #include <stdlib.h>
    int main()
    {
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
        {B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f \t %f\n",i,B,C);
        }system("pause");
        return 0;
    }




    #include <math.h>
    #include <stdio.h>
    #include <stdlib.h>
    int main()
    {
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
        {B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f \t %f\n",i,B,C);
        }system("pause");
        return 0;
    }

    回覆刪除
  51. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B,C;
        float x=1+0.18/12;
              int i;
              for(i=5;i<=50;i=i+5)
    {
              B=A*pow(x,12.*i);
              C=A*exp(0.18*i);
              printf("%d-->%f\t%f\n",i,B,C);
    }
          system("Pause");
          return 0;
    }



    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  52. #include <math.h>
    #include <stdio.h>
    #include <stdlib.h>
    int main()
    {
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
        {B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f \t %f\n",i,B,C);
        }system("pause");
        return 0;
    }




    #include <math.h>
    #include <stdio.h>
    #include <stdlib.h>
    int main()
    {
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
        {B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f \t %f\n",i,B,C);
        }system("pause");
        return 0;
    }

    回覆刪除
  53. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main() {
        int A=500000;
        float b, c ;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
              {
                 b=A*pow(x,12.*i);
                 c=A*exp
    答案
    5-->1221608.875000 1229801.500000
    10-->2984656.500000 3024823.750000
    15-->7292165.500000 7439866.000000
    20-->17816348.000000 18299118.000000
    25-->43529216.000000 45008564.000000
    30-->106351352.000000 110703208.000000
    35-->259839504.000000 272285952.000000
    40-->634844480.000000 669715392.000000
    45-->1551063296.000000 1647234048.000000
    50-->3789585152.000000 4051542016.000000
    請按任意鍵繼續 . . .

    回覆刪除
  54. #include <math.h>
    #include <stdio.h>
    #include <stdlib.h>
    int main()
    {
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
        {B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f \t %f\n",i,B,C);
        }system("pause");
        return 0;
    }




    #include <math.h>
    #include <stdio.h>
    #include <stdlib.h>
    int main()
    {
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
        {B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f \t %f\n",i,B,C);
        }system("pause");
        return 0;
    }

    回覆刪除
  55. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main (){
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
              {
                 B=A*pow(x,12.*i);
                 C=A*exp(0.18*i);
                 printf("%d-->%f \t %f\n",i, B, C);
              }
        system("pause");
        return 0;
    }                       

    回覆刪除
  56. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main(){
        int A=5000000;
        float B, C ;
        float x=1+0.18/12;
        int i;
        for (i=5; i<=50; i=i+5)
               {
                        B=A*pow(x,12.*i);
                        C=A*exp(0.18*i);
                        printf("%d-->%f \t %f\n",i, B, C);
               }
            system("pause");
            return 0;
    }

    答案
    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  57. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
    int A=5000000;
    float B, C;
    float x=1+0.18/12;
    int i;
    for(i=5; i<=50; i=i+5)
    {
    B=A*pow(x,12.*i);
    C=A*exp(0.18*i);
    printf("%d-->%f \t %f\n", i, B, C);
    }

    system("pause");
    return 0;
    }
    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000

    回覆刪除
  58. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
    int A=5000000;
    float B, C;
    float x=1+0.18/12;
    int i;
    for(i=5;i<=50;i=i+5)
    {
    B=A*pow(x,12.*i);
    C=A*exp(0.18*i);
    printf("%d\n-->%f \t %f\n",i, B, C);
    }
    system("pause");
    return 0;
    }

    5
    -->12216089.000000 12298016.000000
    10
    -->29846564.000000 30248238.000000
    15
    -->72921656.000000 74398656.000000
    20
    -->178163472.000000 182991168.000000
    25
    -->435292160.000000 450085664.000000
    30
    -->1063513536.000000 1107032064.000000
    35
    -->2598395136.000000 2722859520.000000
    40
    -->6348444672.000000 6697154048.000000
    45
    -->15510632448.000000 16472340480.000000
    50
    -->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  59. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B,C;
        float x=1+0.18/12;
              int i;
              for(i=5;i<=50;i=i+5)
    {
              B=A*pow(x,12.*i);
              C=A*exp(0.18*i);
              printf("%d-->%f\t%f\n",i,B,C);
    }
          system("Pause");
          return 0;
    }
    5-->12216089.000000     12298016.000000
    10-->29846564.000000    30248238.000000
    15-->72921656.000000    74398656.000000
    20-->178163472.000000   182991168.000000
    25-->435292160.000000   450085664.000000
    30-->1063513536.000000  1107032064.000000
    35-->2598395136.000000  2722859520.000000
    40-->6348444672.000000  6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000

    回覆刪除
  60. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B,C;
        float x=1+0.18/12;
              int i;
              for(i=5;i<=50;i=i+5)
    {
              B=A*pow(x,12.*i);
              C=A*exp(0.18*i);
              printf("%d-->%f\t%f\n",i,B,C);
    }
          system("Pause");
          return 0;
    }
    5-->12216089.000000     12298016.000000
    10-->29846564.000000    30248238.000000
    15-->72921656.000000    74398656.000000
    20-->178163472.000000   182991168.000000
    25-->435292160.000000   450085664.000000
    30-->1063513536.000000  1107032064.000000
    35-->2598395136.000000  2722859520.000000
    40-->6348444672.000000  6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000

    回覆刪除
  61. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B, C;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
        {
         B=A*pow(x,12.*i);
         C=A*exp(0.18*i);
         printf("%d\n-->%f \t %f\n",i, B, C);
         }
    system("pause");
    return 0;
    }

    回覆刪除
  62. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
        int A=5000000;
        float B,C;
        float x=1+0.18/12;
              int i;
              for(i=5;i<=50;i=i+5)
    {
              B=A*pow(x,12.*i);
              C=A*exp(0.18*i);
              printf("%d-->%f\t%f\n",i,B,C);
    }
          system("Pause");
          return 0;
    }

    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  63. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main() {
        int A=5000000;
        float B, C ;
        float x=1+0.18/12;
        int i;
        for (i=5;i<=50;i=i+5)
              {
                 B=A*pow(x,12.*i);
                 C=A*exp(0.18*i);
                 printf("%d-->%f\t %f\n",i, B,C);
              }
        system("pause");
        return 0;
    }

    5-->12216089.000000 12298016.000000
    10-->29846564.000000 30248238.000000
    15-->72921656.000000 74398656.000000
    20-->178163472.000000 182991168.000000
    25-->435292160.000000 450085664.000000
    30-->1063513536.000000 1107032064.000000
    35-->2598395136.000000 2722859520.000000
    40-->6348444672.000000 6697154048.000000
    45-->15510632448.000000 16472340480.000000
    50-->37895852032.000000 40515420160.000000

    回覆刪除
  64. <P>#include &lt;stdio.h&gt;</P>
    <P>#include &lt;stdlib.h&gt;</P>
    <P>#include &lt;math.h&gt;</P>
    <P>int main()</P>
    <P>{</P>
    <P>int A=5000000;</P>
    <P>float B,C;</P>
    <P>float x=+0.18/12;</P>
    <P>int i;</P>
    <P>for(i=5;i&lt;=50;i=i+5)</P>
    <P>{</P>
    <P>B=A*pow(x,12.*i);</P>
    <P>C=A*exp(0.18*i);</P>
    <P>printf("%d--&gt;%f\t,%f\n",i,B,C);</P>
    <P>}</P>
    <P>system("pause");</P>
    <P>return 0;</P>
    <P>}</P>

    答:
    5-->12216089.000000 ,12298016.000000
    10-->29846564.000000 ,30248238.000000
    15-->72921656.000000 ,74398656.000000
    20-->178163472.000000 ,182991168.000000
    25-->435292160.000000 ,450085664.000000
    30-->1063513536.000000 ,1107032064.000000
    35-->2598395136.000000 ,2722859520.000000
    40-->6348444672.000000 ,6697154048.000000
    45-->15510632448.000000 ,16472340480.000000
    50-->37895852032.000000 ,40515420160.000000
    請按任意鍵繼續 . . .

    回覆刪除
  65. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {   
        int A=5000000;
        float B,C;
        float x=1+0.18/12;
        int i;
        for (i=5; i<=50; i=i+5)
        {
        B=A*pow(x,12.*i);
        C=A*exp(0.18*i);
        printf("%d-->%f\t %f\n",i,B,C);
        }
        system("pause");
        return 0;
    }

    回覆刪除
  66. #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    int main()
    {
    int A=5000000;
    float B,C;
    float x=1+0.18/12;
    int i;
    for (i=5; i<=50; i=i+5)
    {
    B=A*pow(x,12.*i);
    C=A*exp(0.18*i);
    printf("%d-->%f\t %f\n",i,B,C);
    }
    system("pause");
    return 0;
    }

    回覆刪除

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