key=48C3B4286FF421A4A328E68AD9E542A4
cipher=
81F277725C7767CA6AD3123572FB1BD02905CEC1640FBF731C6608F67D1DA560
plaintext=?
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2015年5月20日 星期三
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C++用 -1 mask法達到branchless解Leetcode1513 Number of Substrings With Only 1s|Py3 1-liner 其實很容易,想練功,試試一行解,或是把if分岔拿掉 [C++無分岔解請進]
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請用C/C++ 程式計算 S=1*1+2*2+3*3+4*4+.....+20*20=?
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計算你上學期加權平均
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計算你的BMI
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算上學期加權平均
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何謂演算法?並列出一無窮迴圈的範例!
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GCD(123456789,345634567)=?
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問int怎麼存-689這個數字。 int用4個bytes。 答案請用16進位表達。
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55x+27y=gcd
25 則留言:
It' s not hard to use AES-256
B10233167 葉宗翰
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
It' s not hard to use AES-256
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