LeetCode 1344 分針時針夾角：0ms 一行秒殺 (C++/Python)

0ms| 1-liner C++ Py3|1344. Angle Between Hands of a Clock

應徵程式設計師，也會問小學數學，不用懷疑。

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When applying for a programmer position, they'll ask you elementary school math questions, no doubt about it.

#leetcode #1liner  #cplusplus  #python #leetcode1344

[Py3 1-liner請進]

[codes in Leetcode]https://leetcode.com/problems/angle-between-hands-of-a-clock/solutions/8340868/min360-ans-ansbeats-100-by-anwendeng-6u9r/

#anwendeng

class Solution:
    def angleClock(self, h: int, m: int) -> float:
        return 360-A if (A:=max(h*30.0, m*5.5)-min(h*30.0, m*5.5))>180 else A