#include <stdio.h>
#include <stdlib.h>
int main()
{
char s[8][30]={
"CS0160資訊安全實習,丙",
"CS0160資訊安全實習,甲",
"GE0105A勞作教育,丙",
"IM0007程式設計,丙",
"IM0068統計學[二],甲",
"IM0164資訊安全實習,丙",
"OHA001導師,丙",
"OHTA003在校輔導時間,乙"
};
FILE* fp=fopen("score.xls","w");
for (int i=0; i<8; i++)
fprintf(fp,"%d\t%s\n",i,s[i]);
fclose(fp);
system("Pause");
return 0;
}
herrDeng網內搜尋

自訂搜尋
Ads
2009年6月9日 星期二
fopen
修改下列C程式,將你上學期的各科成績出到excel檔!
訂閱:
張貼留言 (Atom)
熱門文章
-
教育部為提昇全民資安素養與電腦防護能力,本部於101年9月5日至11月5日舉辦「全民資安素養自我評量」活動,請在活動期間內踴躍上網檢測資訊安全素養認知程度,並有機會參與抽獎,詳情請參閱活動網站(網址: https://isafe.moe.edu.tw/event
-
C++ Py3 計數排序與partial sum解Leetcode 2300 Successful Pairs of Spells and Potions Portions的極大值小於等於10萬是可進行記數排序的關鍵,既然可以採用記數排序,後面的二元搜尋也可以透過part...
-
Py3 C++ C 2pointer速解Leetcode 11Container With Most Water [Py3 code請進]
-
C++ Pascal三角與模10算術解Leetcode 2221 Find Triangular Sum of an Array 如果採用有支援非常長int的程式語言,mod 10算術就整個省略,就用Pascal三角的性質,可得快速解
-
C C++ GCD LCM解Leetcode難題2197 Replace Non Coprime Numbers in Array 用binary Euclidean algorithm定義gcd,然後定義lcm之後就是用stack [Py3 code請進]
16 則留言:
#include <stdio.h>
#include <stdlib.h>
int main()
{
char s[12][30]={
"體育",
"勞作教育",
"會計學",
"英文",
"操行",
"計算機概論",
"經濟學",
"軍訓",
"微積分",
"管理學",
"中國通史",
"國文",
};
int a[12]={66,75,82,83,84,84,87,88,88,88,88,96};
FILE* fp=fopen("score.xls","w");
for (int i=0; i<12; i++)
fprintf(fp,"%s\t%d\n",s[i],a[i]);
fclose(fp);
system("Pause");
return 0;
}
#include <stdio.h>
#include <stdlib.h>
int main()
{
char s[12][30]={
"勞作教育",
"計算機概論",
"英文",
"體育",
"經濟學",
"管理學",
"中國通史",
"操行",
"會計學",
"軍訓",
"微積分",
"國文",
};
int a[12]={75,76,79,79,80,80,83,84,84,89,92,96};
FILE* fp=fopen("score.xls","w");
for (int i=0; i<12; i++)
fprintf(fp,"%s\t%d\n",s[i],a[i]);
fclose(fp);
system("Pause");
return 0;
}
#include <stdio.h>
#include <stdlib.h>
int main()
{
char s[12][100]={
"CR1001 操行 ",
"GE0101A 國文 ",
"GE0102A 英文 ",
"GE0103A 中國通史 ",
"GE0105A 勞作教育 ",
"IM0004 管理學 ",
"IM0041 計算機概論 ",
"IM0042 微積分(一) ",
"IM0043 經濟學(一) ",
"IM0044 會計學(一) ",
"ML01AA 軍訓 ",
"PE01AA 體育(大一) ",
};
int a[12]={90,99,83,90,75,86,73,72,87,83,89,80};
FILE* fp=fopen("score.xls","w");
for (int i=0; i<12; i++)
fprintf(fp,"%s\t%d\n",s[i],a[i]);
fclose(fp);
system("Pause");
return 0;
}
#include <stdio.h>
#include <stdlib.h>
int main()
{
char s[12][30]={
"操行",
"國文",
"英文",
"中國通史",
"勞作教育",
"管理學",
"計算機概論",
"微積分",
"經濟學",
"會計學",
"軍訓",
"體育",
};
int a[12]={89,78,77,79,85,72,64,60,67,81,81,76};
FILE* fp=fopen("score.xls","w");
for (int i=0; i<12; i++)
fprintf(fp,"%s\t%d\n",s[i],a[i]);
fclose(fp);
system("Pause");
return 0;
}
#include <stdio.h>
#include <stdlib.h>
int main()
{
char s[12][30]={
"國文",
"英文",
"微積分",
"經濟學 ",
"會計學",
"中國通史",
"管理學",
"計算機概論",
"軍訓",
"體育",
"勞作教育",
"操行"
};
int a[12]={80,62,60,75,80,65,84,60,72,72,80,83};
FILE* fp=fopen("score.xls","w");
for (int i=0; i<12; i++)
fprintf(fp,"%s\t%d\n",s[i],a[i]);
fclose(fp);
system("Pause");
return 0;
}
#include <stdio.h>
#include <stdlib.h>
int main(){
char s[12][50]={
"CR1001 操行",
"GE0101A 國文",
"GE0102A 英文",
"GE0103A 中國通史",
"GE0105A 勞作教育",
"IM0004 管理學",
"IM0041 計算機概論",
"IM0042 微積分(一)",
"IM0043 經濟學(一)",
"IM0044 會計學(一)",
"ML01AA 軍訓",
"PE01AA 體育(大一)",
};
int a[12]={83,78,75,80,75,84,77,94,85,85,84,73};
FILE*fp=fopen("score.xls","w");
for (int i=0;i<12;i++)
fprintf(fp,"%s\t%d\n",s[i],a[i]);
fclose(fp);
system("pause");
return 0;
}
#include <stdio.h>
#include <stdlib.h>
int main()
{
char s[12][50]={
"CR1001 操行",
"GE0101A 國文",
"GE0102A 英文",
"GE0103A 中國通史",
"GE0105A 勞作教育",
"IM0004 管理學",
"IM0041 計算機概論",
"IM0042 微積分(一)",
"IM0043 經濟學(一)",
"IM0044 會計學(一)",
"ML01AA 軍訓",
"PE01AA 體育(大一)",
};
int a[]={83,94,65,64,75,77,63,64,80,80,89,73};
FILE* fp=fopen("score.xls","w");
for (int i=0; i<8; i++)
fprintf(fp,"%s\t%d\n",s[i],a[i]);
fclose(fp);
system("Pause");
return 0;
}
#include <stdio.h>
#include <stdlib.h>
int main()
{
char s[11][100]={
"GE0101A 丙 國文 ",
"GE0102A 丙 英文 ",
"GE0103A 丙 中國通史 ",
"IM0004 丙 管理學 ",
"IM0041 丙 計算機概論 ",
"IM0042 丙 微積分(一) ",
"IM0043 丙 經濟學(一) ",
"IM0044 丙 會計學(一) ",
"GE0105A 丙 勞作教育 ",
"ML01AA 丙 軍訓 ",
"PE01AA 丙 體育(大一) ",
};
int a[11]={92,72,88,74,74,77,86,78,75,89,74};
FILE* fp=fopen("score.xls","w");
for (int i=0; i<11; i++)
fprintf(fp,"%s\t%d\n",s[i],a[i]);
fclose(fp);
system("Pause");
return 0;
}
#include <stdio.h>
#include <stdlib.h>
int main()
{
char s[12][30]={
"計算機概論",
"微積分",
"軍訓",
"英文",
"中國通史",
"體育",
"國文",
"經濟學",
"管理學",
"操行",
"勞作教育",
"會計學",
};
int a[12]={60,60,68,70,70,74,75,76,77,84,85,86};
FILE* fp=fopen("score.xls","w");
for (int i=0; i<12; i++)
fprintf(fp,"%s\t%d\n",s[i],a[i]);
fclose(fp);
system("Pause");
return 0;
}
#include <stdio.h>
#include <stdlib.h>
int main()
{
char s[12][30]={
"勞作教育",
"計算機概論",
"英文",
"體育",
"經濟學",
"管理學",
"中國通史",
"操行",
"會計學",
"軍訓",
"微積分",
"國文",
};
int a[12]={75,76,79,62,77,79,88,84,84,91,81,89};
FILE* fp=fopen("score.xls","w");
for (int i=0; i<12; i++)
fprintf(fp,"%s\t%d\n",s[i],a[i]);
fclose(fp);
system("Pause");
return 0;
}
#include <stdio.h>
#include <stdlib.h>
int main()
{
char s[12][30]={
"計算機概論",
"微積分",
"軍訓",
"英文",
"中國通史",
"體育",
"國文",
"經濟學",
"管理學",
"操行",
"勞作教育",
"會計學", };
int a[12]={73,60,63,78,72,66,80,85,72,84,75,87};
FILE* fp=fopen("score.xls","w");
for (int i=0; i<12; i++)
fprintf(fp,"%s\t%d\n",s[i],a[i]);
fclose(fp);
system("Pause");
return 0;
}
#include <stdio.h>
#include <stdlib.h>
int main()
{
char s[11][30]={
"GE0101A 國文",
"GE0102A 英文",
"GE0103A 中國通史",
"GE0105A 勞作教育",
"IM0004 管理學",
"IM0041 計算機概論",
"IM0042 微積分(一)",
"IM0043 經濟學(一)",
"IM0044 會計學(一)",
"ML01AA 軍訓",
"PE01AA 體育(大一)"
};
char c[11][3]={"87","89","87","75","88","81","98","88","83","90","75"};
FILE* fp=fopen("score.xls","w");
for (int i=0; i<8; i++)
fprintf(fp,"%d\t%s\t%s\t\n",i,s[i],c[i]);
fclose(fp);
system("Pause");
return 0;
}
#include <stdio.h>
#include <stdlib.h>
int main()
{
char s[11][35]={
"CR1001操行,89",
"GE0203A英文字彙與閱讀,87",
"GE0204A公民社會概論,81",
"GE0205A人類活動與地球環境變遷,89",
"IM0009資料結構,76",
"IM0021資料庫管理系統,62",
"IM0044會計學(一),79",
"IM0063統計學[一],62",
"IM0103企業電子化,79",
"PE0Z0M體育(韻律),87",
"IM0024會計資訊系統,76"
};
FILE* fp=fopen("score.xls","w");
for (int i=0; i<11; i++)
fprintf(fp,"%d\t%s\n",i,s[i]);
fclose(fp);
system("Pause");
return 0;
}
#include <stdio.h>
#include <stdlib.h>
int main()
{
char s[11][50]={
"英文字彙與閱讀 69",
"公民社會概論 81",
"人類活動與地球環境變遷 80",
"資料結構 90",
"資料庫管理系統 74",
"統計學[一] 78",
"企業電子化 80",
"體育(韻律) 89",
"基礎日文[一般] 61",
"生產管理 62",
"會計資訊系統 73",
};
FILE* fp=fopen("score.xls","w");
for (int i=0; i<11; i++)
fprintf(fp,"%d\t%s\n",i,s[i]);
fclose(fp);
system("Pause");
return 0;
}
#include <stdio.h>
#include <stdlib.h>
int main()
{
char s[10][40]={
"選修 GE3ZA033 甲 科技與人文[科技] 2 60 " ,
"必修 IM0017 乙 系統分析與設計 3 64 ",
"必修 IM0021 乙 資料庫管理系統 3 85 ",
"必修 IM0022 乙 資訊管理實務專題(一) 1 82" ,
"必修 IM0039 乙 資訊管理講座(一) 1 62 ",
"必修 IM0041 乙 計算機概論 3 75 ",
"必修 IM0059 乙 網頁程式設計 3 64 " ,
"選修 IM0069 甲 顧客關係管理 3 92 ",
"必修 IM0095 乙 資訊網路安全 3 37 ",
"必修 PE0Z0L 甲 體育(體適能) 0 86 ",
};
FILE* fp=fopen("score.xls","w");
for (int i=0; i<10; i++)
fprintf(fp,"%d\t%s\n",i,s[i]);
fclose(fp);
system("Pause");
return 0;
}
#include <stdio.h>
#include <stdlib.h>
int main()
{
char s[10][40]={
"必修 GE0103A 中國通史 2 60",
"必修 IM0017 系統分析與設計 3 67",
"必修 IM0021 資料庫管理系統 3 60",
"必修 IM0022 資訊管理實務專題(一) 1 82",
"必修 IM0039 資訊管理講座(一) 1 63",
"必修 IM0044 會計學(一) 3 62",
"必修 IM0059 網頁程式設計 3 60",
"必修 IM0095 資訊網路安全 3 43",
"必修 PE0Z0L 體育(體適能) 0 85",
"選修 MD0030 經濟學(一) 3 60" ,
};
FILE* fp=fopen("score.xls","w");
for (int i=0; i<10; i++)
fprintf(fp,"%d\t%s\n",i,s[i]);
fclose(fp);
system("Pause");
return 0;
}
張貼留言