這是Herr Deng桑的教學blog,主要處理作業與班導事務,另外還有數位小品。
0 1 2 3 4 r_k 33 17 16 1 0 q_k 0 1 1 16 x_k 1 0 1 1 17 y_k 0 1 1 2 33 ====> 33(-1+17k)+17(2-33k)=1
其中 x_(k+1)=q_kx_k+x_(k-1) y_(k+1)=q_ky_k+y_(k-1)
x=1+k28y=-2+k55gcd=1
x=1+K28y=-2+K55答案: 1
x=1y=-2gcd=1
x= 1*55y= -2*27gcd= 1
y=-2+k55x=1+k28gcd=1
gcd=1x=1y=-2
gcd = 1x= 1y= -2驗證:55(1)+27(-2)=gcd55+(-54)=gcdgcd= 1
gcd = 1x= 1y= -2
x=1+k28,y=-2+k55gcd=1
x=(1)+k28y=(-2)+k55gcd=1
x=1+k28 y=-2+k55gcd=1
x = 1 + k28y = -2 + k55gcd = 1答案是 1
x=1+K28y=-2+K55gcd=1
X=1+k28Y=-2+k55gcd=1
X = 1y = -2gcd = 55+(-54) = 1
x = 1 + k28y = -2 + k55gcd = 1
x=1+k27y=-2+k55gcd=1
張貼留言
72 則留言:
x=1+k28
y=-2+k55
gcd=1
x=1+K28
y=-2+K55
答案: 1
x=1+k28
y=-2+k55
gcd=1
x=1
y=-2
gcd=1
x= 1*55
y= -2*27
gcd= 1
y=-2+k55
x=1+k28
gcd=1
x=1+k28
y=-2+k55
gcd=1
gcd=1
x=1
y=-2
gcd = 1
x= 1
y= -2
驗證:
55(1)+27(-2)=gcd
55+(-54)=gcd
gcd= 1
gcd = 1
x= 1
y= -2
x=1+k28
y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
gcd=1
x=1
y=-2
x=1
y=-2
gcd=1
x=1+k28,y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=(1)+k28
y=(-2)+k55
gcd=1
x=1+k28,y=-2+k55
gcd=1
gcd = 1
x= 1
y= -2
x=1+k28 y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
x= 1*55
y= -2*27
gcd= 1
x = 1 + k28
y = -2 + k55
gcd = 1
答案是 1
y=-2+k55
x=1+k28
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1+K28
y=-2+K55
gcd=1
X=1+k28
Y=-2+k55
gcd=1
x=1+K28
y=-2+K55
答案: 1
x=1+k28
y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1
y=-2
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1
y=-2
gcd=1
gcd = 1
x= 1
y= -2
x=1
y=-2
gcd=1
y=-2+k55
x=1+k28
gcd=1
x=(1)+k28
y=(-2)+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1
y=-2
gcd=1
x=1
y=-2
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
X = 1
y = -2
gcd = 55+(-54) = 1
x=1
y=-2
gcd=1
x=1+k28
y=-2+k55
gcd=1
x = 1 + k28
y = -2 + k55
gcd = 1
x=1+k28
y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1
y=-2
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1+k27
y=-2+k55
gcd=1
gcd=1
x=1
y=-2
x=1+k28
y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1+K28
y=-2+K55
答案: 1
x=1+k28
y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
gcd=1
x=1
y=-2
y=-2+k55
x=1+k28
gcd=1
x=1+k28
y=-2+k55
gcd=1
x=1+k28
y=-2+k55
gcd=1
張貼留言