貪婪計數Python C++解Leetcode 2491 Divide Players Into Teams of Equal Skill

貪婪計數Python C++解Leetcode 2491  Divide Players Into Teams of Equal Skill

貪婪演算+counting sort加上2-pointer這樣就完成打敗100趴的快速C++解答[Python code請進]

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Greedy algorithm+ counting sort + 2-pointer complete the quick C++ solution to defeat 100%.

[codes on Leetcode]https://leetcode.com/problems/divide-players-into-teams-of-equal-skill/solutions/5866450/greedy-sort-frequency-count-2-pointers-14ms-beats-100/

[Leetcode Playlist]https://www.youtube.com/watch?v=B1GQlUN08lk&list=PLYRlUBnWnd5IdDHk2BjqXwesydU17z_xk

[Python C++計數速解Leetcode 945 Minimum Increment to Make Array Unique]https://www.youtube.com/watch?v=tS-kunvQwcc

class Solution:
    def dividePlayers(self, skill: List[int]) -> int:
        freq=[0]*1001
        Sum, xMin, xMax=0, 1000, 1
        for x in skill:
            freq[x]+=1
            Sum+=x
            xMin=min(xMin, x)
            xMax=max(xMax, x)
        n_2=len(skill)//2
        if Sum%n_2!=0: return -1
        team_skill=Sum//n_2
 
        chemi=0
        l, r=xMin, xMax
        while l<r:
            fL, fR=freq[l], freq[r]
            if l+r!=team_skill or fL!=fR: return -1
            chemi+=fL*l*r
            l+=1
            r-=1
        if l==r and l*2==team_skill:
            chemi+=freq[l]//2*l*l
        return chemi