0ms C++ Py3 1-line prefix sum速解Leetcode 2574 Left and Right Sum Differences

0ms C++ Py3 1-line prefix sum速解Leetcode 2574  Left and Right Sum Differences

3 different solutions are given in this video.

標示easy也確實可用簡化的方式來解，如果解答不是線性解，就要加油囉。Key word:Prefix sum

[Py3 1-liner請進]

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The solution marked "easy" can indeed be solved using simplified methods. However, if the solution is not linear, you'll need to work harder. Key word: Prefix sum

[codes on Leetcode]https://leetcode.com/problems/left-and-right-sum-differences/solutions/8316192/compute-running-sumsbeats-100-by-anwende-11jy/

 #anwendeng 

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here are the timestamps for the key sections of the walkthrough for LeetCode problem 2574, "Left and Right Sum Differences":

00:00 - Introduction to problem 2574.

00:44 - Explaining the definitions of leftSum and rightSum.

01:43 - Walking through Example 1.

02:49 - Walking through Example 2.

03:01 - Reviewing constraints.

03:14 - C++ solution walkthrough and initial implementation.

05:23 - Optimizing the C++ code (avoiding extra vector allocation).

06:14 - Python solution walkthrough using itertools.accumulate and a one-liner approach.

class Solution:
    def leftRightDifference(self, nums: List[int]) -> List[int]:
        return (L:=list(accumulate(nums, initial=0))) and [abs(L[-1]-x-2*l) for l, x in zip(L, nums)]